7.4 Summarizing Data by Groups
7.4.2 Solution
Use group_by()
and summarise()
from the dplyr package, and specify the operations to do:
library(MASS) # Load MASS for the cabbages data set
library(dplyr)
%>%
cabbages group_by(Cult, Date) %>%
summarise(
Weight = mean(HeadWt),
VitC = mean(VitC)
)#> `summarise()` has grouped output by 'Cult'. You can override using the
#> `.groups` argument.
#> # A tibble: 6 x 4
#> # Groups: Cult [2]
#> Cult Date Weight VitC
#> <fct> <fct> <dbl> <dbl>
#> 1 c39 d16 3.18 50.3
#> 2 c39 d20 2.8 49.4
#> 3 c39 d21 2.74 54.8
#> 4 c52 d16 2.26 62.5
#> 5 c52 d20 3.11 58.9
#> 6 c52 d21 1.47 71.8
7.4.3 Discussion
There are few things going on here that may be unfamiliar if you’re new to dplyr and the tidyverse in general.
First, let’s take a closer look at the cabbages
data set. It has two factors that can be used as grouping variables: Cult
, which has levels c39
and c52
, and Date
, which has levels d16
, d20
, and d21
. It also has two numeric variables, HeadWt
and VitC
:
cabbages#> Cult Date HeadWt VitC
#> 1 c39 d16 2.5 51
#> 2 c39 d16 2.2 55
#> ...<56 more rows>...
#> 59 c52 d21 1.5 66
#> 60 c52 d21 1.6 72
Finding the overall mean of HeadWt
is simple. We could just use the mean()
function on that column, but for reasons that will soon become clear, we’ll use the summarise()
function instead:
library(dplyr)
summarise(cabbages, Weight = mean(HeadWt))
#> Weight
#> 1 2.593333
The result is a data frame with one row and one column, named Weight
.
Often we want to find information about each subset of the data, as specified by a grouping variable. For example, suppose we want to find the mean of each Cult
group. To do this, we can use summarise()
with group_by()
.
<- group_by(cabbages, Cult)
tmp summarise(tmp, Weight = mean(HeadWt))
#> # A tibble: 2 x 2
#> Cult Weight
#> <fct> <dbl>
#> 1 c39 2.91
#> 2 c52 2.28
The command first groups the data frame cabbages
based on the value of Cult
. There are two levels of Cult
, c39
and c52
, so there are two groups. It then applies the summarise()
function to each of these data frames; it calculates Weight
by taking the mean()
of the HeadWt
column in each of the sub-data frames. The resulting summaries for each group are assembled into a data frame, which is returned.
You can imagine that the cabbages
data is split up into two separate data frames, then summarise()
is called on each data frame (returning a one-row data frame for each), and then those results are combined together into a final data frame. This is actually how things worked in dplyr’s predecessor, plyr, with the ddply()
function.
The syntax of the previous code used a temporary variable to store results. That’s a little verbose, so instead, we can use %>%
, also known as the pipe operator, to chain the function calls together. The pipe operator simply takes what’s on its left and substitutes it as the first argument of the function call on the right. The following two lines of code are equivalent:
group_by(cabbages, Cult)
# The pipe operator moves `cabbages` to the first argument position of group_by()
%>% group_by(Cult) cabbages
The reason it’s called a pipe operator is that it lets you connect function calls together in sequence to form a pipeline of operations. Another common term for this is a different metaphor: chaining.
So the first argument of the function call is in a different place. So what? The advantages become apparent when chaining is involved. Here’s what it would look like if you wanted to call group_by()
and then summarise()
without making use of a temporary variable. Instead of proceeding left to right, the computation occurs from the inside out:
summarise(group_by(cabbages, Cult), Weight = mean(HeadWt))
Using a temporary variable, as we did earlier, makes it more readable, but a more elegant solution is to use the pipe operator:
%>%
cabbages group_by(Cult) %>%
summarise(Weight = mean(HeadWt))
Back to summarizing data. Summarizing the data frame by grouping using more variables (or columns) is simple: just give it the names of the additional variables. It’s also possible to get more than one summary value by specifying more calculated columns. Here we’ll summarize each Cult
and Date
group, getting the average of HeadWt
and VitC
:
%>%
cabbages group_by(Cult, Date) %>%
summarise(
Weight = mean(HeadWt),
Vitc = mean(VitC)
)#> `summarise()` has grouped output by 'Cult'. You can override using the
#> `.groups` argument.
#> # A tibble: 6 x 4
#> # Groups: Cult [2]
#> Cult Date Weight Vitc
#> <fct> <fct> <dbl> <dbl>
#> 1 c39 d16 3.18 50.3
#> 2 c39 d20 2.8 49.4
#> 3 c39 d21 2.74 54.8
#> 4 c52 d16 2.26 62.5
#> 5 c52 d20 3.11 58.9
#> 6 c52 d21 1.47 71.8
Note
You might have noticed that it says that the result is grouped by
Cult
, but notDate
. This is because thesummarise()
function removes one level of grouping. This is typically what you want when the input has one grouping variable. When there are multiple grouping variables, this may or may not be the what you want. To remove all grouping, useungroup()
, and to add back the original grouping, usegroup_by()
again.
It’s possible to do more than take the mean. You may, for example, want to compute the standard deviation and count of each group. To get the standard deviation, use sd()
, and to get a count of rows in each group, use n()
:
%>%
cabbages group_by(Cult, Date) %>%
summarise(
Weight = mean(HeadWt),
sd = sd(HeadWt),
n = n()
)#> `summarise()` has grouped output by 'Cult'. You can override using the
#> `.groups` argument.
#> # A tibble: 6 x 5
#> # Groups: Cult [2]
#> Cult Date Weight sd n
#> <fct> <fct> <dbl> <dbl> <int>
#> 1 c39 d16 3.18 0.957 10
#> 2 c39 d20 2.8 0.279 10
#> 3 c39 d21 2.74 0.983 10
#> 4 c52 d16 2.26 0.445 10
#> 5 c52 d20 3.11 0.791 10
#> 6 c52 d21 1.47 0.211 10
Other useful functions for generating summary statistics include min()
, max()
, and median()
. The n()
function is a special function that works only inside of the dplyr functions summarise()
, mutate()
and filter()
. See ?summarise
for more useful functions.
The n()
function gets a count of rows, but if you want to have it not count NA
values from a column, you need to use a different technique. For example, if you want it to ignore any NA
s in the HeadWt
column, use sum(!is.na(Headwt))
.
7.4.3.1 Dealing with NAs
One potential pitfall is that NA
s in the data will lead to NA
s in the output. Let’s see what happens if we sprinkle a few NA
s into HeadWt
:
<- cabbages # Make a copy
c1 $HeadWt[c(1, 20, 45)] <- NA # Set some values to NA
c1
%>%
c1 group_by(Cult) %>%
summarise(
Weight = mean(HeadWt),
sd = sd(HeadWt),
n = n()
)#> # A tibble: 2 x 4
#> Cult Weight sd n
#> <fct> <dbl> <dbl> <int>
#> 1 c39 NA NA 30
#> 2 c52 NA NA 30
The problem is that mean()
and sd()
simply return NA
if any of the input values are NA.
Fortunately, these functions have an option to deal with this very issue: setting na.rm=TRUE
will tell them to ignore the NA
s.
%>%
c1 group_by(Cult) %>%
summarise(
Weight = mean(HeadWt, na.rm = TRUE),
sd = sd(HeadWt, na.rm = TRUE),
n = n()
)#> # A tibble: 2 x 4
#> Cult Weight sd n
#> <fct> <dbl> <dbl> <int>
#> 1 c39 2.9 0.822 30
#> 2 c52 2.23 0.828 30
7.4.3.2 Missing combinations {#_missing_combinations}
If there are any empty combinations of the grouping variables, they will not appear in the summarized data frame. These missing combinations can cause problems when making graphs. To illustrate, we’ll remove all entries that have levels c52
and d21
. The graph on the left in Figure 7.2 shows what happens when there’s a missing combination in a bar graph:
# Copy cabbages and remove all rows with both c52 and d21
<- filter(cabbages, !( Cult == "c52" & Date == "d21" ))
c2 <- c2 %>%
c2a group_by(Cult, Date) %>%
summarise(Weight = mean(HeadWt))
ggplot(c2a, aes(x = Date, fill = Cult, y = Weight)) +
geom_col(position = "dodge")
To fill in the missing combination (Figure 7.2, right), use the complete()
function from the tidyr package – which is also part of the tidyverse. Also, the grouping for c2a
must be removed, with ungroup()
; otherwise it will return too many rows.
library(tidyr)
<- c2a %>%
c2b ungroup() %>%
complete(Cult, Date)
ggplot(c2b, aes(x = Date, fill = Cult, y = Weight)) +
geom_col(position = "dodge")
# Copy cabbages and remove all rows with both c52 and d21
<- filter(cabbages, !( Cult == "c52" & Date == "d21" ))
c2 <- c2 %>%
c2a group_by(Cult, Date) %>%
summarise(Weight = mean(HeadWt))
#> `summarise()` has grouped output by 'Cult'. You can override using the
#> `.groups` argument.
ggplot(c2a, aes(x = Date, fill = Cult, y = Weight)) +
geom_col(position = "dodge")
#> This is an untitled chart with no subtitle or caption.
#> It has x-axis 'Date' with labels d16, d20 and d21.
#> It has y-axis 'Weight' with labels 0, 1, 2 and 3.
#> There is a legend indicating fill is used to show Cult, with 2 levels:
#> c39 shown as strong reddish orange fill and
#> c52 shown as brilliant bluish green fill.
#> The chart is a bar chart with 5 vertical bars.
#> Bar 1 spans horizontally from 0.55 to 1, and spans vertically from 0 to 3.18 with fill colour strong reddish orange which maps to Cult = c39.
#> Bar 2 spans horizontally from 1.55 to 2, and spans vertically from 0 to 2.8 with fill colour strong reddish orange which maps to Cult = c39.
#> Bar 3 spans horizontally from 2.55 to 3.45, and spans vertically from 0 to 2.74 with fill colour strong reddish orange which maps to Cult = c39.
#> Bar 4 spans horizontally from 1 to 1.45, and spans vertically from 0 to 2.26 with fill colour brilliant bluish green which maps to Cult = c52.
#> Bar 5 spans horizontally from 2 to 2.45, and spans vertically from 0 to 3.11 with fill colour brilliant bluish green which maps to Cult = c52.
library(tidyr)
<- c2a %>%
c2b ungroup() %>%
complete(Cult, Date)
ggplot(c2b, aes(x = Date, fill = Cult, y = Weight)) +
geom_col(position = "dodge")
#> This is an untitled chart with no subtitle or caption.
#> It has x-axis 'Date' with labels d16, d20 and d21.
#> It has y-axis 'Weight' with labels 0, 1, 2 and 3.
#> There is a legend indicating fill is used to show Cult, with 2 levels:
#> c39 shown as strong reddish orange fill and
#> c52 shown as brilliant bluish green fill.
#> The chart is a bar chart with 6 vertical bars.
#> Bar 1 is centered horizontally at 0.78, and spans vertically from 0 to 3.18 with fill colour strong reddish orange which maps to Cult = c39.
#> Bar 2 is centered horizontally at 1.77, and spans vertically from 0 to 2.8 with fill colour strong reddish orange which maps to Cult = c39.
#> Bar 3 is centered horizontally at 2.78, and spans vertically from 0 to 2.74 with fill colour strong reddish orange which maps to Cult = c39.
#> Bar 4 is centered horizontally at 1.23, and spans vertically from 0 to 2.26 with fill colour brilliant bluish green which maps to Cult = c52.
#> Bar 5 is centered horizontally at 2.22, and spans vertically from 0 to 3.11 with fill colour brilliant bluish green which maps to Cult = c52.
#> Bar 6 is centered horizontally at 3.22, and spans vertically from NA to NA with fill colour brilliant bluish green which maps to Cult = c52.
When we used complete()
, it filled in the missing combinations with NA
. It’s possible to fill with a different value, with the fill
parameter. See ?complete
for more information.